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File:Squaring the circle.svg

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Summary

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Description Illustrates the dimensions required for squaring a unit circle, which would require a square with side lengths equal to the squareroot of pi. Plynn9 authored it to improve the current illustration in the "Squaring the Circle" wikipedia article, which lacks dimensions. I made a vector version of the image.
Date Original PNG: 6 November 2006; SVG: 16 February 2007
Source Pd-self image by Plynn9
Author Original PNG by Plynn9; SVG by Alexei Kouprianov
Other versions Squaring the circle.png: 

Licensing

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Public domain I, the copyright holder of this work, release this work into the public domain. This applies worldwide.
In some countries this may not be legally possible; if so:
I grant anyone the right to use this work for any purpose, without any conditions, unless such conditions are required by law.
W3CiThe source code of this SVG is valid.
 
This vector image was created with Sodipodi by Alexei Kouprianov.

File history

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Date/TimeThumbnailDimensionsUserComment
current14:05, 12 April 2014Thumbnail for version as of 14:05, 12 April 2014281 × 281 (2 KB)Jc86035 (talk | contribs)removed line-height with text editor just to make it W3C compliant
14:00, 12 April 2014Thumbnail for version as of 14:00, 12 April 2014281 × 281 (2 KB)Jc86035 (talk | contribs)Removed sodipodi artifacts and other bits using SVGCleaner; changed font to open-source Linux Libertine O
17:04, 16 February 2007Thumbnail for version as of 17:04, 16 February 2007281 × 281 (4 KB)Alexei Kouprianov (talk | contribs){{Information |Description=Illustrates the dimensions required for squaring a unit circle, which would require a square with side lengths equal to the squareroot of pi. Plynn9 authored it to improve the current illustration in the "Squarin
16:42, 16 February 2007Thumbnail for version as of 16:42, 16 February 2007281 × 281 (4 KB)Alexei Kouprianov (talk | contribs){{Information |Description=Illustrates the dimensions required for squaring a unit circle, which would require a square with side lengths equal to the squareroot of pi. Plynn9 authored it to improve the current illustration in the "Squarin

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